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標題:
What is the answer of this fomula?
發問:
(a-x)*(b-x)*(c-x)...*(z-x)
最佳解答:
(a-x)*(b-x)*(c-x)...*(z-x)=1 !! Because one of the terms will be ( x-x ) , and this equals 0 . As we know that , a^o is always 1! ( a is for all values , except 0 )
其他解答:
a*0 = 0 (a multiplied by 0 is 0), a^0 = 1 (a to the power of 0 is 1), thus a*0 is not a^0 by all means.|||||A wrong answer is chosen instead of the other correct one. It's a pity!|||||u r wrong the answer should be 0 while * is for times and ^ is for index... (...)*(x-x) = (...)*0 = 0|||||I think the below mean that the answer is 0 because (x-x)=0, so the entire product is zero.
What is the answer of this fomula?
發問:
(a-x)*(b-x)*(c-x)...*(z-x)
最佳解答:
(a-x)*(b-x)*(c-x)...*(z-x)=1 !! Because one of the terms will be ( x-x ) , and this equals 0 . As we know that , a^o is always 1! ( a is for all values , except 0 )
其他解答:
a*0 = 0 (a multiplied by 0 is 0), a^0 = 1 (a to the power of 0 is 1), thus a*0 is not a^0 by all means.|||||A wrong answer is chosen instead of the other correct one. It's a pity!|||||u r wrong the answer should be 0 while * is for times and ^ is for index... (...)*(x-x) = (...)*0 = 0|||||I think the below mean that the answer is 0 because (x-x)=0, so the entire product is zero.
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