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標題:
因式分解的問題
發問:
1, a^2-9b^2 2, 1分之3b^2-12 3, 2x^3-16 4, 6x^2-11xy-10y^2 5, x^2+8x+12 6, 6x^2+7x-20 7, (a^2-a-72)+(ab+8b) 因式分解上邊7題
最佳解答:
1) a^2-9b^2 =(a+3b)(a-3b) 2) 1分之3b^2-12 =3b^2-12 =3(b^2-4) =3(b+2)(b-2) 3) 2x^3-16 =2(x^3-8) =2(x-2)(x^2+2x+4) 4) 6x^2-11xy-10y^2 =(2x-5)(3x+2) 5) x^2+8x+12 =(x+6)(x+2) 6) 6x^2+7x-20 =(3x-4)(2x+5) 7) (a^2-a-72)+(ab+8b) =(a-9)(a+8)+b(a+8) =(a+8)(a+b-9) 2008-08-05 12:10:14 補充： 我係絕對冇抄上面果位，只係我回答中ge時候，佢已經遞交了。
其他解答:
1, a^2-9b^2 = a^2-(3b)^2 = (a- 3b)(a+3b) 2, 1分之3b^2-12 = 1/3b^2-12 =b^2-4 =b^2-2^2 =(b-2)(b+2) 3, 2x^3-16 =(2) (x^3-8) =(2) (x^3-2^3) =(2) (x-2)(x^2+4x-4) 4, 6x^2-11xy-10y^2 =(2x-5y)(3x+2y) 5, x^2+8x+12 =(x+2)(x+6) 6, 6x^2+7x-20 =(2x+5)(3x-4) 7, (a^2-a-72)+(ab+8b) =(a+8)(a-9) + b(a+8) =(a+8)(a-9+b)
因式分解的問題
發問:
1, a^2-9b^2 2, 1分之3b^2-12 3, 2x^3-16 4, 6x^2-11xy-10y^2 5, x^2+8x+12 6, 6x^2+7x-20 7, (a^2-a-72)+(ab+8b) 因式分解上邊7題
最佳解答:
1) a^2-9b^2 =(a+3b)(a-3b) 2) 1分之3b^2-12 =3b^2-12 =3(b^2-4) =3(b+2)(b-2) 3) 2x^3-16 =2(x^3-8) =2(x-2)(x^2+2x+4) 4) 6x^2-11xy-10y^2 =(2x-5)(3x+2) 5) x^2+8x+12 =(x+6)(x+2) 6) 6x^2+7x-20 =(3x-4)(2x+5) 7) (a^2-a-72)+(ab+8b) =(a-9)(a+8)+b(a+8) =(a+8)(a+b-9) 2008-08-05 12:10:14 補充： 我係絕對冇抄上面果位，只係我回答中ge時候，佢已經遞交了。
其他解答:
1, a^2-9b^2 = a^2-(3b)^2 = (a- 3b)(a+3b) 2, 1分之3b^2-12 = 1/3b^2-12 =b^2-4 =b^2-2^2 =(b-2)(b+2) 3, 2x^3-16 =(2) (x^3-8) =(2) (x^3-2^3) =(2) (x-2)(x^2+4x-4) 4, 6x^2-11xy-10y^2 =(2x-5y)(3x+2y) 5, x^2+8x+12 =(x+2)(x+6) 6, 6x^2+7x-20 =(2x+5)(3x-4) 7, (a^2-a-72)+(ab+8b) =(a+8)(a-9) + b(a+8) =(a+8)(a-9+b)
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