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標題:
maths geometry
發問:
The line y=2x-8 meets the coordinate axes at A and B.The line AB is a diameter of the circle.Find the equation of the circle.
Put x = 0, y = -8 Put y = 0, 2x - 8 = 0 and hence x = 4 Mid-point of AB : ((-8+0)/2 , (4+0)/2) = (-4, 2) AB = root(8^2 + 4^2) = 4root5 Hence the equation of circle is (x + 4)^2 + (y - 2)^2 = (2root5)^2 x^2 + y^2 + 8x - 4y = 0
其他解答:
maths geometry
發問:
The line y=2x-8 meets the coordinate axes at A and B.The line AB is a diameter of the circle.Find the equation of the circle.
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最佳解答:Put x = 0, y = -8 Put y = 0, 2x - 8 = 0 and hence x = 4 Mid-point of AB : ((-8+0)/2 , (4+0)/2) = (-4, 2) AB = root(8^2 + 4^2) = 4root5 Hence the equation of circle is (x + 4)^2 + (y - 2)^2 = (2root5)^2 x^2 + y^2 + 8x - 4y = 0
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