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when y=ab^xBy taking point A(2,0.15) and B(5,0.68)0.15=2m+c------10.68=5m+c------2If 2 -1 form0.53=3mm=0.177so log b=0.177 b= 10^0.177b=1.5sub m(b) into 10.15=2(0.177)+cc=-0.204so log a=-0.204a=10^-0.204a=0.63We can calculate a=0.63 and b=1.50The equation is y=0.63*1.5^xabove... 顯示更多 when y=ab^x By taking point A(2,0.15) and B(5,0.68) 0.15=2m+c------1 0.68=5m+c------2 If 2 -1 form 0.53=3m m=0.177 so log b=0.177 b= 10^0.177 b=1.5 sub m(b) into 1 0.15=2(0.177)+c c=-0.204 so log a=-0.204 a=10^-0.204 a=0.63 We can calculate a=0.63 and b=1.50 The equation is y=0.63*1.5^x above correct or not ? other, do not understanding ---> y=ax^b, how to calculate it as below: taking point A(0.78,0.60) and B(1.38,1.81) answer : a=0.11 and b=2.0 the equation is y=0.11x^2 Please step by step teach me,thankyou so much.
最佳解答:
university professor can help to solve the enquiry.
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y=ab^x and y=ax^b發問:
when y=ab^xBy taking point A(2,0.15) and B(5,0.68)0.15=2m+c------10.68=5m+c------2If 2 -1 form0.53=3mm=0.177so log b=0.177 b= 10^0.177b=1.5sub m(b) into 10.15=2(0.177)+cc=-0.204so log a=-0.204a=10^-0.204a=0.63We can calculate a=0.63 and b=1.50The equation is y=0.63*1.5^xabove... 顯示更多 when y=ab^x By taking point A(2,0.15) and B(5,0.68) 0.15=2m+c------1 0.68=5m+c------2 If 2 -1 form 0.53=3m m=0.177 so log b=0.177 b= 10^0.177 b=1.5 sub m(b) into 1 0.15=2(0.177)+c c=-0.204 so log a=-0.204 a=10^-0.204 a=0.63 We can calculate a=0.63 and b=1.50 The equation is y=0.63*1.5^x above correct or not ? other, do not understanding ---> y=ax^b, how to calculate it as below: taking point A(0.78,0.60) and B(1.38,1.81) answer : a=0.11 and b=2.0 the equation is y=0.11x^2 Please step by step teach me,thankyou so much.
最佳解答:
university professor can help to solve the enquiry.
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